Answer:
A
Step-by-step explanation:
First, simplify the numerator:
[tex]\frac{3 }{\sqrt{3} + \sqrt{x} } \\[/tex]
Next, multiply the numerator and denominator by the opposite of the denominator to rationalize the expression.
[tex]\frac{3}{\sqrt{3}+\sqrt{x} }*\frac{\sqrt{3}-\sqrt{x} }{\sqrt{3}-\sqrt{x}}[/tex]
Finally, evaluate the denominator by multiplying them together.
[tex]\frac{3(\sqrt{3}-\sqrt{x})} {(\sqrt{3}+\sqrt{x})(\sqrt{3}-\sqrt{x})}[/tex]
Simplify:
[tex]\frac{3(\sqrt{3}-\sqrt{x})} {3-x}[/tex]
And done! :)
