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What is the mass of 0.714 moles of Mercury (I) Chloride (Hg2Cl2)?

A. 472.2 amu
B. 340.0 amu
C. 472.2 g
D. 337.2 g
E. Both A and C

Respuesta :

dexteright02
Data:

m (Sample Mass) = ? 
n (Number of moles) = 0.714 mol
MM (Molar Mass) of Mercury (I) Chloride ([tex] Hg_{2} Cl_{2} [/tex])
Hg = 2*200.59 = 401.18 amu
Cl = 2*35.453 = 70.906 amu
----------------------------------------
Molar Mass [tex] Hg_{2} Cl_{2} [/tex] = 401.18 + 70.906 = 472.086 ≈ 472.09 amu or 472.09 g/mol

Formula:

[tex]n = \frac{m}{MM} [/tex]

Solving:


[tex]n = \frac{m}{MM} [/tex]
[tex]0.714 = \frac{m}{472.09} [/tex]
[tex]m = 337.07226\:\to\:\boxed{\boxed{m\approx 337 g}} \end{array}}\qquad\quad\checkmark[/tex]

Answer:
By approximation would be letter D) 337.2 g


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