juanburciaga330 juanburciaga330

31-01-2022
Mathematics

contestada

The equation of a circle is pi(2x+3)^2
What is the least possible integer value of x for the circle to exist? Please explain.

Respuesta :

corbomatthew corbomatthew

04-02-2022

Answer: x = -1

Step-by-step explanation:

The radius needs to be positive, so 2x + 3 > 0. Solving for x, we get x > -3/2. The smallest integer larger than -3/2 is -1, so x = –1.

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