Respuesta :

Eyadaqrabawi

slope = (y2-y1)/(x2-x1)

[tex] \frac{ - 1}{7} = \frac{n - 10}{ - 1 - - 3} = \frac{n - 10}{2} [/tex]

[tex] \frac{ - 2}{7} = n - 10 [/tex]

[tex] - 2 = 7n - 70 \\ 7n = 68 \\ n = 9.7[/tex]

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