Answer:
51.61% of O in C₂H₆O₂
Explanation:
First find the total mass: C = 12 , H = 1 , O = 16
total mass of C₂H₆O₂ = 12 * 2 + 1 * 6 + 16 * 2 = 62
so total mass of oxygen, O₂ in this is: 16 * 2 = 32
- now find O₂ percentage in C₂H₆O₂
⇒ ( 32 / 62 ) * 100
⇒ 51.61%
