The standard deviation is 1.98. Option A is correct.
The standard deviation formula is given as
- [tex]\sigma = \sqrt{\frac{SS}{n} }[/tex]
where:
- SS is the sum of squares = 200
- n is the sample size = 51
Substitute the given parameters into the formula to have:
[tex]\sigma = \sqrt{\frac{200}{51} }\\\sigma = \sqrt{3.922}\\\sigma = 1.980[/tex]
Hence the standard deviation is 1.98
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