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Is s=[tex]\frac{Ft^{2} }{2m}[/tex] a correct conversion from a=[tex]\frac{at^{2} }{2}[/tex]?

I just substituted "a" as [tex]\frac{F}{m}[/tex]

Respuesta :

RedGeek2531

Answer:

well your substitution method is correct but make sure to double check the original formula

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