What is the pH of a buffer made by combining 10.0mL of 0.51 M CH3NH2 with 10.0 mL of 0.61 M CH3NH3Cl? Kb CH3NH2 = 4.4 x 10-4

Respuesta :

Answer:

10.57

Explanation:

pOH = pKb + log(acid/base)