Answer:
Below in bold.
Step-by-step explanation:
f(x) = x^3 - x
Finding the derivative:
f'(x) = 3x^2 - 1
At a maximum/minimum
3x^2 - 1 = 0
x^2 = 1/3
x = +/- √(1/3) or +/- 0.57735
As x < 0 the answer is -0.58 to 2 s.f's.
This gives a maximum value of f(x) as the second derivative 6x with x = -0.58 gives a negative value.
