Respuesta :

abasudoh1

Step-by-step explanation:

T0 = a³+4

T1 = a⁴x a¹ +4

T2= a³ + a³ + 4

T3= a⁴ + a⁴* a² + 4

T4= a⁴ + a⁴ x a¹ + 4

T5= a³ + a³ + a⁴+4

caylus

Answer:

hello,

Step-by-step explanation:

c(1)=5

c(2)=9

c(2)-c(1)=9-5=4

c(2)=9

c(3)=13

c(3)-c(2)=13-9=4

c(3)=13

c(4)=17

c(4)-c(3)=17-13=4

c(4)=17

c(5)=21

c(5)-c(4)=21-17=4

for n=1,2,...,k :

c(n+1)-c(n)=4 and c(n+1)=4*(n+1)+1=4n+5

c(1)=1

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