Look at the attachment
The line bisects the cord which we have to find
- Length of chord=12cm
- Half of the cord=12/2=6cm
- Radius=10cm
Its a right angle triangle
- using Pythagorean theorem
[tex]\boxed{\sf P^2=H^2-B^2}[/tex]
[tex]\\ \Large\sf\longmapsto P=\sqrt{H^2-B^2}[/tex]
[tex]\\ \Large\sf\longmapsto P=\sqrt{10^2-6^2}[/tex]
[tex]\\ \Large\sf\longmapsto P=\sqrt{100-36}[/tex]
[tex]\\ \Large\sf\longmapsto P=\sqrt{64}[/tex]
[tex]\\ \Large\sf\longmapsto P=8cm[/tex]
Distance of the chord from centre is 8cm.
