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A mass of 68.45 g of nickel (II) sulfate hydrate, NiSO4∙ nH2O, loses 28.40 g upon dehydration. What is the hydration number of this compound? (Find n.)

Respuesta :

Answer:

n=4

Explanation:

n= (154.75×28.40)÷(68.45×18)

n=3.5

n=4(approximately)