Answer:
9 units
Step-by-step explanation:
Given
[tex]Length = 8[/tex]
[tex]Width = 4[/tex]
[tex]Height = 1[/tex]
Required
Determine the length of the longest segment
To do this, we use:
[tex]Longest = \sqrt{Length^2 + Width^2 + Height^2}[/tex]
So, we have:
[tex]Longest = \sqrt{8^2 + 4^2 + 1^2}[/tex]
[tex]Longest = \sqrt{64 + 16 + 1}[/tex]
[tex]Longest = \sqrt{81}[/tex]
Take positive square root
[tex]Longest = 9[/tex]
Hence, the length of the longest segment is 9 units
