Answer:
y = 0, -2
Step-by-step explanation:
Factor out the common term 3y.
[tex]3y( {y}^{2} + 4y + 4) = 0[/tex]
Rewrite y² + 4y + 4 in the form of a² + 2ab + b², where a = y and b = 2.
[tex]3y( {y}^{2} + 2(y)(2) + {2}^{2} ) = 0[/tex]
Use square sum: (a + b)² = a² + 2ab + b².
[tex]3y(y + 2) ^{2} = 0[/tex]
solve for y.
y = 0, -2.
therefor, the answer for this equation is 0, - 2.
