Respuesta :
Answer:
= −0.26
= 0.4219
Step-by-step explanation:
Given:
Sample1: Â 98.1 Â 98.8 Â 97.3 Â 97.5 Â 97.9
Sample2: 98.7 Â 99.4 Â 97.7 Â 97.1 Â 98.0
Sample 1 Â Â Â Â Â Sample 2 Â Â Â Â Â Â Â Difference d
98.1 Â Â Â Â Â Â Â Â Â Â Â Â 98.7 Â Â Â Â Â Â Â Â Â Â Â -0.6 Â
98.8 Â Â Â Â Â Â Â Â Â Â Â 99.4 Â Â Â Â Â Â Â Â Â Â Â -0.6
97.3 Â Â Â Â Â Â Â Â Â Â Â Â 97.7 Â Â Â Â Â Â Â Â Â Â Â -0.4
97.5 Â Â Â Â Â Â Â Â Â Â Â Â 97.1 Â Â Â Â Â Â Â Â Â Â Â Â 0.4
97.9 Â Â Â Â Â Â Â Â Â Â Â Â 98.0 Â Â Â Â Â Â Â Â Â Â Â -0.1
To find:
Find the values of  and
d overbar ( ) Â is the sample mean of the differences which is calculated by dividing the sum of all the values of difference d with the number of values i.e. n = 5
= ∑d/n
= (−0.6 −0.6 −0.4 +0.4 −0.1) / 5
= −1.3 / 5
= −0.26
s Subscript d is the sample standard deviation of the difference which is calculated as following:
= √∑( - )²/ n-1
=
√
  =  √ (−0.6 − (−0.26 ))² + (−0.6 − (−0.26))² + (−0.4 − (−0.26))² + (0.4 − Â
                                  (−0.26))² + (−0.1 − (−0.26))² / 5−1
= Â
=
=
= 0.4219
= 0.4219
Subscript d ​represent
μ represents the mean of differences in body temperatures measured at 8 AM and at 12 AM of population.
Step-by-step explanation: