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  • 28-04-2021
  • Mathematics
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What is the sum of an 8 term geometric series if the first term is -11 and the last term is 859,375 and the common ratio is -5

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nuuk nuuk
  • 29-04-2021

Answer:716,144

Step-by-step explanation:

Given

No of the terms in GP [tex]n=8[/tex]

First-term [tex]a=-11[/tex]

last term [tex]a_n=859,375\quad (ar^{n-1})[/tex]

Common ratio [tex]r=-5[/tex]

The Sum of a GP is given by

[tex]S_n=\dfrac{a(1-r^n)}{1-r}\quad \quad [r<1][/tex]

Put the values

[tex]\Rightarrow S_n=\dfrac{-11(1-(-5)^8)}{1-(-5)}\\\\\Rightarrow S_n=\dfrac{-11\times -390624}{6}\\\\\Rightarrow S_n=\dfrac{42,96,864}{6}=716,144[/tex]

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