grdotz2591 grdotz2591
  • 30-03-2021
  • Mathematics
contestada

If 0 < b ≤ 90 and cos(11b + 2) = sin(12b − 4), what is the value of b? b = 3 b = 4 b = 5 b = 6

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MrRoyal
MrRoyal MrRoyal
  • 30-03-2021

Answer:

[tex]b = 6[/tex]

Step-by-step explanation:

Given

[tex]0<b\le 90[/tex]

[tex]\cos(11b + 2) = \sin(12b - 4)[/tex]

Required

Find b

To solve this, we make use of the following trigonometry rule:

If [tex]\cos(\alpha) = \sin(\beta)[/tex]

Then: [tex]\alpha + \beta = 90[/tex]

So:

[tex]11b + 2 = 12b - 4[/tex]

Collect like terms

[tex]11b - 12b = - 4 - 2[/tex]

[tex]-b = - 6[/tex]

Multiply both sides by -1

[tex]b = 6[/tex]

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