31-01-2021
Mathematics

contestada

Log16 (x squared - 3x + 12) = 1

Respuesta :

31-01-2021

log_(16)(x^2 - 3x + 12) = 1
x^2 - 3x +12 = 16
x^2 - 3x - 4 = 0
x = [3 ± √(3^2 - 4(1)(-4))]/[2(1)] = [3 ± 5]/2 = 4, -1

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