avrian86
avrian86 avrian86
  • 27-01-2021
  • Mathematics
contestada

Please help with this question

Please help with this question class=

Respuesta :

imtiazkalwar
imtiazkalwar imtiazkalwar
  • 27-01-2021

Answer:

[tex]c=17[/tex] ft

Step-by-step explanation:

Base=b=8 ft

Hyp=c=?

Perp=a=15 ft

Applying Pythagoras theorem

[tex]c=\sqrt{a^{2} + b^{2} }[/tex]

[tex]c=\sqrt{15^{2} + 8^{2} }[/tex]

[tex]c=\sqrt{289 }\\c=17[/tex]

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