Answer:
[tex]M_{acid}=0.075M[/tex]
Explanation:
Hello!
In this case, since the reaction between NaOH and HNO3 is:
[tex]NaOH+HNO_3\rightarrow NaNO_3+H_2O[/tex]
Whereas there is a 1:1 mole ratio between the acid and base, thus, we can write:
[tex]M_{acid}V_{acid}=M_{base}V_{base}[/tex]
In such a way, solving for the concentration of the acid, HNO3, we obtain:
[tex]M_{acid}=\frac{M_{base}V_{base}}{V_{acid}}[/tex]
Therefore, by plugging in we obtain:
[tex]M_{acid}=\frac{0.12L*0.2M}{0.32L}\\\\ M_{acid}=0.075M[/tex]
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