chanesther12
chanesther12
30-12-2020
Chemistry
contestada
please help me ASAP PLEASE
Respuesta :
desolate
desolate
30-12-2020
24 cm^3 CO2 / 1 * 1 dcm^3 / 1000 cm^3 * 1 mol / 24 dcm^3 = 0.001 mol of CO3 is required
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