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g A cylinder of length 2.75 m, radius 0.420 m, and mass 14.7 kg is rotated at an angular speed of 3.70 rad/s around an axis parallel to the length of the cylinder and through its center. Find the magnitude of the cylinder's angular momentum.

Respuesta :

Answer:

4.792 kgm²/s

Explanation:

Given that

Length of the cylinder, l = 2.75 m

Radius of the cylinder, r = 0.42 m

Mass of the cylinder, m = 14.7 kg

Angular speed of rotation, v = 3.7 rad/s

The magnitude of a cylinders angular momentum is given by the formula

L = I * v, where

I = moment of inertia about the axis given by mr²/2

I = (14.7 * 0.42²) / 2

I = 2.59 / 2

I = 1.295 kgm

L = I * v

L = 1.295 * 3.7

L = 4.792 kgm²/s

Therefore, the angular momentum of the cylinder is 4.792 kgm²/s