Answer:
[tex]A = 101.5825591635[/tex]°
Step-by-step explanation:
We can use the law of cosines. We have a triangle with side lengths as attached. (See image.)
So we want to solve for angle A.
We do this by using:
[tex]cos(A)=(b^2 + c^2 - a^2) / (2bc)[/tex]
Here we have:
a = 36
b = 27
c = 19
So we plug in to get:
[tex]cos(A)=(27^2 +19^2-36^2)/(2*27*19)[/tex]
[tex]cos(A)=-0.20077972709[/tex]
[tex]A = 101.5825591635[/tex]°
