Answer:
Explanation:
H₂SO₄
density of solution = 1.183 g / mL
= 1183 g / L
1.183 kg / L
volume of 1 kg of solution = 1 / 1.183 L
= .8453 L
molality of H₂SO₄ = 3.22 m
3.22 moles in 1 kg of solvent
3.22 moles in .8453 L of solution
[ volume of solute is negligible ]
molarity of solution
= 3.22 / .8453 M
= 3.81 M
