A and B play 12 games of chess of which 6 are won by A,4 are won by B,and 2 end in a draw. They agree to play a tournament consisting of 3 games. Find the probability that (a) A wins all 3 games, (b) 2 games end in a draw, (c) A and B win alternately, (d) B wins at least 1 game.

Respuesta :

Answer:

A. 2 x 3=6  B. 6 x 2=12

Step-by-step explanation:

so you multiply 2 and 3 and it make 6 and then you multiply 6 and 2 and it makes 12.