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a painter chargers $12 an hour while his son charges $6 an hour. if the father and son worked the same amount of time together on a job, how many hours did each of them work if their combined charge for their labor was 108

Respuesta :

eunice1234

Answer: 6 hours

Step-by-step explanation:

Let x= the number of hours they've worked

12x+6x=108

Combine like terms

18x=108

Divide 18 on both sides

18/18 x=108/18

x=6

Hope this helps!! :)

Please let me know if you have any question

jackzhai

Answer:

We set they worked x hours.

12x + 6x ＝108

18x＝108

X＝6

They have to work 6hours together

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