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What must be the tension of a string 202 cm long and 3 x 10-2 Kg / m per unit length (µ) for it to emit a sound of 78 Hz?

Respuesta :

MathPhys

Answer:

2980 N

Explanation:

The fundamental frequency of a string is:

f₁ = √(T/µ) / (2L)

78 Hz = √(T / (0.03 kg/m)) / (2 (2.02 m))

315.12 m/s = √(T / (0.03 kg/m))

99,300 m²/s² = T / (0.03 kg/m)

T = 2980 N

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