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  • 26-07-2020
  • Mathematics
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evaluate sin^-1(sin5)

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Аноним Аноним
  • 26-07-2020

−π2≤sin−1x≤π2  

3π2≤5≤2π

−π2≤5−2π≤0≤π2

sin(5–2π)=sin5

Thus, sin−1(sin5)=5−2π

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