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29-06-2020
Mathematics

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use the three conditions to show that function f(x)=2x^2 +3x - 1 is continuous at x=0.

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ronhagrid310 ronhagrid310

29-06-2020

Answer:

f(x) = 2x^2 +3x - 1

f'(x) = 4x + 3

f''(x) = 4

f(0) = 2(0)^2 + 3(0) - 1 = -1 (valid)

f'(0) = 4(0) + 3 = 3 (valid)

f''(0) = 4 (valid)

=> f(x) is continous at x = 0

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