Answer:
[tex]Q = 934.911\,kJ[/tex]
Explanation:
The energy needed to boil 17.3 moles of ice is:
[tex]Q = (17.3\,mol)\cdot \left[\left(40.5\,\frac{kJ}{mol} \right)+ \left(\frac{4.186}{1000}\,\frac{kJ}{g\cdot ^{\circ}C} \right)\cdot \left(\frac{18.015\,g }{1\,mol} \right)\cdot (100^{\circ}C-0^{\circ}C)+\left(6\,\frac{kJ}{mol}\right)\right][/tex][tex]Q = 934.911\,kJ[/tex]
