Answer:
(10, 0.205π)
Step-by-step explanation:
The magnitude of the coordinates is:
[tex]\|\vec r \| = \sqrt{8^{2}+6^{2}}[/tex]
[tex]\|\vec r \| = 10[/tex]
Besides, the angle associated with the coordinates is:
[tex]\theta = \tan^{-1}\left(\frac{6}{8} \right)[/tex]
[tex]\theta = 0.205\pi[/tex]
The polar coordinates are (10, 0.205π)
