Katantoleilseab
Katantoleilseab
31-07-2016
Mathematics
contestada
Simplify: e^(1+lnx)
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Benjamin16
Benjamin16
06-08-2016
[tex]\boxed{x = a^{\log_{a}x}} \implies x = e^{\ln x}[/tex]
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[tex]e^{1 + \ln x} = e \cdot e^{\ln x} =\boxed{ e \cdot x}[/tex]
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