Answer:
0.182M Ba(OH)₂
Explanation:
The reaction of barium metal (Ba) with H₂O is:
Ba + 2H₂O → Ba(OH)₂ + H₂
25g of Ba are:
25g Ba × (1mol / 137.327g) = 0.182 moles of Ba. Based in the reaction, 1 mole of Ba produces 1 mole of Ba(OH)₂. That means you will produce 0.182 moles of Ba(OH)₂. If the whole volume of your solution is 1.00L, the concentration of barium hydroxide is:
0.182 moles of Ba(OH)₂ / 1.00L = 0.182M Ba(OH)₂
