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Assume that charge −q is placed on the top plate, and +q is placed on the bottom plate. What is the magnitude of the electric field E between the plates? Express E in terms of q and other quantities given in the introduction, in addition to ϵ0 and any other constants needed..

Respuesta :

Answer:

 [tex]E=\frac{q}{\epsilon_oA}[/tex]  

Explanation:

Let the area of each plate be A.

From Gauss Law,

[tex]\phi=\frac{q}{\epsilon_o}[/tex]

[tex]\phi=E.A[/tex]

[tex]\Rightarrow E.A=\frac{q}{\epsilon_o}\\\Rightarrow E=\frac{q}{\epsilon_oA}[/tex]

Thus, using Gauss law, electric field between the plates is:

[tex]E=\frac{q}{\epsilon_oA}[/tex]

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