Answer:
0.346 M
Explanation:
Let's consider the following neutralization reaction.
NaOH + HCl → NaCl + H₂O
24.7 mL of 0.140 M NaOH react. The reacting moles are:
24.7 × 10⁻³ L × 0.140 mol/L = 3.46 × 10⁻³ mol
The molar ratio of NaOH to HCl is 1:1. The moles of HCl that reacted are 3.46 × 10⁻³ moles.
3.46 × 10⁻³ moles of HCl are contained in 10.0 mL. The molarity of HCl is:
3.46 × 10⁻³ mol/ 10.0 × 10⁻³ L = 0.346 M
