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An ideal gas in a balloon is kept in thermal equilibrium with its constant-temperature surroundings. How much work is done if the pressure is slowly reduced and the balloon expands to five times its original size?
The balloon initially has a pressure of 815.0 Pa and has a volume of 0.70 m^3.

Respuesta :

Answer:

W = 918.18 J

Explanation:

given,

Initial pressure of balloon = 815.0 Pa

Initial Volume = 0.7 m³

volume expand by = 5 times

From the ideal gas equation

    PV = nRT

And work is equal to

[tex]W = n RT ln(\dfrac{5V_0}{V_0})[/tex]

[tex]W =P_0V_0 ln(5)[/tex]

[tex]W =815 \times 0.7\times ln(5)[/tex]

W = 918.18 J

Work done by expanding the balloon is equal to W = 918.18 J

   

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