Answer:
a) 2
b) 3
c) 1
Step-by-step explanation:
The standard error (SE) is given as:
SE = s ÷ √n
here,
s = √[SS ÷ (n - 1)]
Therefore,
We get,
SE = [tex]\sqrt{\frac{SS}{n(n-1)}}[/tex]
Therefore,
For a) n = 4 with SS = 48
SE = [tex]\sqrt{\frac{48}{4(4-1)}}[/tex]
or
SE = √4
or
SE = 2
For b) n = 6 with SS = 270
SE = [tex]\sqrt{\frac{270}{6(6-1)}}[/tex]
or
SE = √9
or
SE = 3
For c) n = 12 with SS = 132
SE = [tex]\sqrt{\frac{132}{12(12-1)}}[/tex]
or
SE = √1
or
SE = 1
