Answer:
Explanation:
Given
total height h=2 m
acceleration is given by
a=g-bv
after falling 0.5 m Styrofoam acquires its terminal velocity
remaining distance to fall is 2-0.5=1.5 m
time taken after acquiring terminal velocity is 5 s
[tex]v_{terminal}=\frac{1.5}{5}=0.3 m/s[/tex]
at terminal velocity a=0
thus g-bv=0
[tex]b=\frac{9.8}{0.3}=32.66[/tex]
at t=0 acceleration
[tex]a=9.8-32.66\cdot 0[/tex]
[tex]a=9.8 m/s^2[/tex]
(c)acceleration when speed is 0.15 m/s
[tex]a=9.8-32.66\cdot 0.15=4.89 m/s^2[/tex]
