binboyjay123 binboyjay123
  • 30-10-2019
  • Mathematics
contestada

f(x) = -2(3x+1)(x+2)(x-3) in standard form

Respuesta :

funkeyusuff52
funkeyusuff52 funkeyusuff52
  • 31-10-2019

Answer:

f(x) = -6x^3+4x^2+38x+12

Step-by-step explanation:

f(x)=-2(3x+1)(x+2)(x-3)

      = -2(3x+1)(x^2-x-6)

      = -2(3x^3-3x^2-18x+x^2-x-6)

      = -2(3x^3-2x^2-19x-6)

      = -6x^3+4x^2+38x+12

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