The first problem x-4 / 2x-8 x-3 / 5x What you would do for this is cross equation the whole thing by; 1x-4=5x 1x-3=2x-8 The 1x's cancel out and -4=5x -3=2x-8 -7=7x-8 +8= +8 1 =7x then divide 7x by 1 and your answer for that one would be x=1.
And then the second problem 3x / 2x+5 x-3 / (x+2)(x-3) You would solve by; first combining like terms which are the ones in parenthesis and you would get; 3x=2x-6 x-3=2x+5 The 2x's cancel out 3x=-6 x-3=5 +3 +3 4x=8 Then you would divide both sides by 4 and get x=2 as your answer.
Sorry it took me so long I was double checking my work. But I hope it helps!
