Answer:
θ = 67.4242°
Explanation:
The law of refraction, or Snell's law, states that:
[tex]{\text{n1} \sin (\text{$\theta $1})}={\text{n2} \sin (\text{$\theta $2})}[/tex]
With n1 = v1/c n2 = v2/c
Therefore:
[tex]\frac{\text{v1}}{\text{v2}}=\frac{\sin (\text{$\theta $1})}{\sin (\text{$\theta $2})}[/tex]
If 1 denotes the air-side:
v1 = 340 m/s
v2 = 1510 m/s
θ1 = 12°
[tex]\theta2 =\sin ^{-1}\left(\frac{\text{v1} \sin (\text{$\theta $1})}{\text{v2}}\right)[/tex]
θ2= 67.4242°
