Answer:
C
Step-by-step explanation:
Case 1
x-12 < 15
+12 each side
x < 27
Check case 1
|27-12| = 15
|15| = 15
15 = 15
So x<27 is correct but we still have to evaluate for the possibility of case 2
Case 2
x-12 < -15
+12 each side
x < -3
Check case 2
|-3-12| = 15
|-15| = 15
15 = 15
So -3 is also valid
Therefore your answer would be
C. x<27 and x<-3
