Answer:
[tex]x_1=e^{18} \quad \text{and} \quad x_2=e^{12}[/tex]
Step-by-step explanation:
We want to solve the equations
[tex]\ln(x_2)=12 \quad \text{and} \quad x_1=e^{6}x_2[/tex]
For the first equation we have
[tex]x_2=e^{12}[/tex]
and so, for the second equation holds
[tex]x_1=e^{6}\cdot e^{12}=e^{6+12}=e^{18}.[/tex]
