Answer:
Rate of change of length as a function of time is given by [tex]\frac{dL(t)}{dt}=34.416e^{-0.18t}[/tex]
Explanation:
The length as function of time is given by[tex]L(t)=200(1-0.956e^{-0.18t})[/tex]
Differentiating with respect to time we get
[tex]\frac{dL(t)}{dt}=\frac{d(200(1-0.956e^{-0.18t}))}{dt}\\\\\frac{dL(t)}{dt}=200\frac{d(1-0.956e^{-0.18t})}{dt}\\\\=200\times 0.18\times 0.956e^{-0.18t}\\\\\frac{dL(t)}{dt}=34.416e^{-0.18t}[/tex]
