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Two cars leave towns 480 kilometers apart at the same time and travel toward each other. One car's rate is 20 kilometers per hour less than the other's. If they meet in 3 hours, what is the rate of the slower car

Respuesta :

Answer:

70 km/h

Explanation:

Let the velocity of car A is v km/h, thus the velocity of car B is (v - 20) km/h.

They meet after 3 hours.

Distance traveled by car A in 3 hours = v x 3 = 3 v

Distance traveled by car B in 3 hours = (v - 20) x 3 = 3v - 60

Total distance traveled is 480 km

So, 3 v + 3 v - 60 = 480

6 v - 60 = 480

6 v = 540

v = 90 km/h

Thus, the speed of car A is 90 km/h and the speed of car B is 90 - 20 = 70 km/h.

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