contestada

A shaft of circular cross section (diameter = 3 in) is subjected to a bending moment of 3200 lb- ft. Determine the bending stress at the surface of the shaft.

Respuesta :

Answer:

 [tex]\sigma =145.62 MPa[/tex]

Explanation:

Given that

Diameter  of shaft=3 in      (1 in=0.0254 m)

Bending moment=3200 lb-ft      (1 lb-ft=1.35 N-m)

We know that bending stress in circular shaft given as

[tex]\sigma =\dfrac{32M}{\pi d^3}[/tex]

Where M is the bending moment and d is the diameter of shaft.

Given that M=4338.61 N-m

            d=0.0672 m

Now by putting the values

[tex]\sigma =\dfrac{32\times 4338.61}{\pi \times 0.0672^3}[/tex]

So  [tex]\sigma =145.62 MPa[/tex]

Otras preguntas