Answer: 0.6915
Step-by-step explanation:
Given : [tex]\text{Mean}=\mu=10^{\circ}C[/tex]
[tex]\text{Standard deviation}=\sigma=10^{\circ}C[/tex]
Since , the distribution follows a Normal distribution.
The formula to calculate the z-score is given by :-
[tex]z=\dfrac{x-\mu}{\sigma}[/tex]
For x=[tex]15^{\circ}C[/tex]
[tex]z=\dfrac{15-10}{10}=0.5[/tex]
The p-value = [tex]P(z\leq0.5)=0.6914625\approx0.6915[/tex]
Hence, the required probability : 0.6915
