Respuesta :

[tex]\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-1}{ h},\stackrel{-4}{ k})\qquad \qquad radius=\stackrel{2}{ r} \\\\[-0.35em] ~\dotfill\\[2em] [x-(-1)]^2+[y-(-4)]^2=2^2\implies (x+1)^2+(y+4)^2=4[/tex]

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