Answer:
8y^2 (y+2)
Step-by-step explanation:
8y^3 + 16y^2
both terms contain an 8 and a y^2 so we can factor them out
[tex]8y^3=8y^2(y)\\\\16y^2=8y^2(2)\\\\8y^3+16y^2=8y^2(y)+8y^2(2)=8y^2(y+2)[/tex]
