lacyjoness
lacyjoness
28-09-2018
Mathematics
contestada
Please help me!!!!!!!!!!
Respuesta :
choixongdong
choixongdong
28-09-2018
-5x √(28x^2y^3)
= -5x √(4 * 7 x^2y^2 * y)
= -5x √[(2xy)^2 * (7y)]
= - 5x * 2xy √(7y)
=
-10x^2y √(7y)
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